Repeating the different mating combinations for the Blue geneīlue X Blue = 25% Black (without the gene) 50% Blue (with 1 gene) and 25% Splash (with 2 genes). However the female will only pass the trait on to her sons. This is unlike the barred factor, where the male will pass the trait on to his sons and daughters. Both a Blue male and female will pass the trait on to both sexes in the offspring. If the bird has 2 doses of the gene it is a Splash.īlue is not sex-linked. If one parent has the Blue gene then about 50% of the offspring should have it. If one Blue gene is present, it will be Blue. If the Blue gene isn't present the chicken is black. One Blue gene will change a Black bird to Blue one. 2 Blue genes will change Black to a whitish bird with random darker Blue/Black feathers, a Splash. Blue is dominant, and effects Black only. There is no need to do test matings to find out if it is present. You can tell if a chicken has blue or not straight away, just by looking at it. One Black gene and one Blue gene = Blue (or Bl/bl = Blue). This gene acts to dilute Black (shown as bl) to Blue in one dose (it is more correctly grey, being between Black and White, but called blue in poultry terminology). In Australia, the gene responsible for Blue, either in lacing or in ground colour is the Blue diluter (written as Bl ). NOW, I am NOT saying I know a lot, as I don't, I only know enough to get me by with my chosen coloursīlue X Blue = 50% Blue, 25% Splash, 25% Blackīut this also depends on how many chickens you hatch for the mixed hatches (where Blue is used to breed from), as theoretical % will require average hatchings of 1,000 birds for these % In memory of Lance Hicks, without whom I would not understand the genetics of poultry to the extent I do The theory of Mendel's Law and the Blue Gene
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